-7p^2-p-4=-10

Solution for -7p^2-p-4=-10 equation:

-7p^2-p-4=-10

We move all terms to the left:

-7p^2-p-4-(-10)=0

We add all the numbers together, and all the variables

-7p^2-1p+6=0

a = -7; b = -1; c = +6;
Δ = b2-4ac
Δ = -12-4·(-7)·6
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-13}{2*-7}=\frac{-12}{-14}
=6/7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+13}{2*-7}=\frac{14}{-14}
=-1
$